1198139953 has 2 divisors, whose sum is σ = 1198139954. Its totient is φ = 1198139952.

The previous prime is 1198139941. The next prime is 1198139977. The reversal of 1198139953 is 3599318911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 908901904 + 289238049 = 30148^2 + 17007^2 .

It is a cyclic number.

It is not a de Polignac number, because 1198139953 - 2²¹ = 1196042801 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1198139897 and 1198139906.

It is not a weakly prime, because it can be changed into another prime (1198139993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 599069976 + 599069977.

It is an arithmetic number, because the mean of its divisors is an integer number (599069977).

Almost surely, 2^1198139953 is an apocalyptic number.

It is an amenable number.

1198139953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1198139953 is an equidigital number, since it uses as much as digits as its factorization.

1198139953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 262440, while the sum is 49.

The square root of 1198139953 is about 34614.1582737469. The cubic root of 1198139953 is about 1062.1092311186.

The spelling of 1198139953 in words is "one billion, one hundred ninety-eight million, one hundred thirty-nine thousand, nine hundred fifty-three".