Base | Representation |
---|---|
bin | 100011101101010… |
… | …0010101001011001 |
3 | 10002111111211002022 |
4 | 1013122202221121 |
5 | 4423210434433 |
6 | 314520144225 |
7 | 41456010341 |
oct | 10732425131 |
9 | 3074454068 |
10 | 1198139993 |
11 | 565356346 |
12 | 295308075 |
13 | 1612c299b |
14 | b51a7d21 |
15 | 702be698 |
hex | 476a2a59 |
1198139993 has 2 divisors, whose sum is σ = 1198139994. Its totient is φ = 1198139992.
The previous prime is 1198139977. The next prime is 1198140001. The reversal of 1198139993 is 3999318911.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1194946624 + 3193369 = 34568^2 + 1787^2 .
It is a cyclic number.
It is not a de Polignac number, because 1198139993 - 24 = 1198139977 is a prime.
It is not a weakly prime, because it can be changed into another prime (1198139953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 599069996 + 599069997.
It is an arithmetic number, because the mean of its divisors is an integer number (599069997).
Almost surely, 21198139993 is an apocalyptic number.
It is an amenable number.
1198139993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1198139993 is an equidigital number, since it uses as much as digits as its factorization.
1198139993 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 472392, while the sum is 53.
The square root of 1198139993 is about 34614.1588515451. The cubic root of 1198139993 is about 1062.1092429381.
The spelling of 1198139993 in words is "one billion, one hundred ninety-eight million, one hundred thirty-nine thousand, nine hundred ninety-three".
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