Base | Representation |
---|---|
bin | 100011101101010… |
… | …0010101000110101 |
3 | 10002111111211000222 |
4 | 1013122202220311 |
5 | 4423210434312 |
6 | 314520144125 |
7 | 41456010260 |
oct | 10732425065 |
9 | 3074454028 |
10 | 1198139957 |
11 | 565356313 |
12 | 295308045 |
13 | 1612c2971 |
14 | b51a7cd7 |
15 | 702be672 |
hex | 476a2a35 |
1198139957 has 24 divisors (see below), whose sum is σ = 1493994624. Its totient is φ = 940384512.
The previous prime is 1198139953. The next prime is 1198139977. The reversal of 1198139957 is 7599318911.
It is not a de Polignac number, because 1198139957 - 22 = 1198139953 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1198139899 and 1198139908.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1198139953) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 66848 + ... + 82854.
It is an arithmetic number, because the mean of its divisors is an integer number (62249776).
Almost surely, 21198139957 is an apocalyptic number.
1198139957 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
It is an amenable number.
1198139957 is a deficient number, since it is larger than the sum of its proper divisors (295854667).
1198139957 is a wasteful number, since it uses less digits than its factorization.
1198139957 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16085 (or 16068 counting only the distinct ones).
The product of its digits is 612360, while the sum is 53.
The square root of 1198139957 is about 34614.1583315267. The cubic root of 1198139957 is about 1062.1092323005.
The spelling of 1198139957 in words is "one billion, one hundred ninety-eight million, one hundred thirty-nine thousand, nine hundred fifty-seven".
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