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119822424613 is a prime number
BaseRepresentation
bin110111110010111111…
…0010001101000100101
3102110021122000211212021
41233211332101220211
53430344020041423
6131013510223141
711441211542623
oct1574576215045
9373248024767
10119822424613
11468a86a9101
121b280354ab1
13b3b7481c88
145b29920513
1531b45ca95d
hex1be5f91a25

119822424613 has 2 divisors, whose sum is σ = 119822424614. Its totient is φ = 119822424612.

The previous prime is 119822424611. The next prime is 119822424629. The reversal of 119822424613 is 316424228911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108016080964 + 11806343649 = 328658^2 + 108657^2 .

It is a cyclic number.

It is not a de Polignac number, because 119822424613 - 21 = 119822424611 is a prime.

Together with 119822424611, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 119822424613.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119822424611) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59911212306 + 59911212307.

It is an arithmetic number, because the mean of its divisors is an integer number (59911212307).

Almost surely, 2119822424613 is an apocalyptic number.

It is an amenable number.

119822424613 is a deficient number, since it is larger than the sum of its proper divisors (1).

119822424613 is an equidigital number, since it uses as much as digits as its factorization.

119822424613 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 165888, while the sum is 43.

The spelling of 119822424613 in words is "one hundred nineteen billion, eight hundred twenty-two million, four hundred twenty-four thousand, six hundred thirteen".