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119834931253 is a prime number
BaseRepresentation
bin110111110011010110…
…1111111000000110101
3102110022111120020202011
41233212231333000311
53430410220300003
6131015034244221
711441423052262
oct1574655770065
9373274506664
10119834931253
1146904770574
121b284586671
13b3b9c4075b
145b2b458269
1531b574b46d
hex1be6b7f035

119834931253 has 2 divisors, whose sum is σ = 119834931254. Its totient is φ = 119834931252.

The previous prime is 119834931193. The next prime is 119834931259. The reversal of 119834931253 is 352139438911.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92307807684 + 27527123569 = 303822^2 + 165913^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-119834931253 is a prime.

It is a super-2 number, since 2×1198349312532 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 119834931197 and 119834931206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119834931259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59917465626 + 59917465627.

It is an arithmetic number, because the mean of its divisors is an integer number (59917465627).

Almost surely, 2119834931253 is an apocalyptic number.

It is an amenable number.

119834931253 is a deficient number, since it is larger than the sum of its proper divisors (1).

119834931253 is an equidigital number, since it uses as much as digits as its factorization.

119834931253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 699840, while the sum is 49.

The spelling of 119834931253 in words is "one hundred nineteen billion, eight hundred thirty-four million, nine hundred thirty-one thousand, two hundred fifty-three".