Base | Representation |
---|---|
bin | 10110010100101011… |
… | …11011110000111101 |
3 | 1010221020021221001210 |
4 | 23022111323300331 |
5 | 144021034311140 |
6 | 5301121155033 |
7 | 602664054660 |
oct | 131225736075 |
9 | 33836257053 |
10 | 11984682045 |
11 | 50a004a006 |
12 | 23a578ba79 |
13 | 118cc3054b |
14 | 8199916d7 |
15 | 4a2246d80 |
hex | 2ca57bc3d |
11984682045 has 64 divisors (see below), whose sum is σ = 22421422080. Its totient is φ = 5352492288.
The previous prime is 11984682043. The next prime is 11984682077. The reversal of 11984682045 is 54028648911.
It is not a de Polignac number, because 11984682045 - 21 = 11984682043 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 11984681985 and 11984682003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11984682043) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3220696 + ... + 3224414.
It is an arithmetic number, because the mean of its divisors is an integer number (350334720).
Almost surely, 211984682045 is an apocalyptic number.
11984682045 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11984682045 is a deficient number, since it is larger than the sum of its proper divisors (10436740035).
11984682045 is a wasteful number, since it uses less digits than its factorization.
11984682045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4434.
The product of its (nonzero) digits is 552960, while the sum is 48.
The spelling of 11984682045 in words is "eleven billion, nine hundred eighty-four million, six hundred eighty-two thousand, forty-five".
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