11985343 has 2 divisors, whose sum is σ = 11985344. Its totient is φ = 11985342.

The previous prime is 11985307. The next prime is 11985353. The reversal of 11985343 is 34358911.

It is a strong prime.

It is an emirp because it is prime and its reverse (34358911) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11985343 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11985299 and 11985308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11985353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5992671 + 5992672.

It is an arithmetic number, because the mean of its divisors is an integer number (5992672).

Almost surely, 2^11985343 is an apocalyptic number.

11985343 is a deficient number, since it is larger than the sum of its proper divisors (1).

11985343 is an equidigital number, since it uses as much as digits as its factorization.

11985343 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12960, while the sum is 34.

The square root of 11985343 is about 3461.9854130253. The cubic root of 11985343 is about 228.8495989979.

The spelling of 11985343 in words is "eleven million, nine hundred eighty-five thousand, three hundred forty-three".