Base | Representation |
---|---|
bin | 10110010100111101… |
… | …01110000111111111 |
3 | 1010221101121221202212 |
4 | 23022132232013333 |
5 | 144022132013341 |
6 | 5301242411035 |
7 | 603022460336 |
oct | 131236560777 |
9 | 33841557685 |
10 | 11986985471 |
11 | 50a138266a |
12 | 23a6500a7b |
13 | 1190558b16 |
14 | 819dd0d1d |
15 | 4a254e5eb |
hex | 2ca7ae1ff |
11986985471 has 2 divisors, whose sum is σ = 11986985472. Its totient is φ = 11986985470.
The previous prime is 11986985443. The next prime is 11986985473. The reversal of 11986985471 is 17458968911.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11986985471 - 218 = 11986723327 is a prime.
It is a super-3 number, since 3×119869854713 (a number of 31 digits) contains 333 as substring.
Together with 11986985473, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11986985471.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11986985473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5993492735 + 5993492736.
It is an arithmetic number, because the mean of its divisors is an integer number (5993492736).
Almost surely, 211986985471 is an apocalyptic number.
11986985471 is a deficient number, since it is larger than the sum of its proper divisors (1).
11986985471 is an equidigital number, since it uses as much as digits as its factorization.
11986985471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4354560, while the sum is 59.
The spelling of 11986985471 in words is "eleven billion, nine hundred eighty-six million, nine hundred eighty-five thousand, four hundred seventy-one".
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