Base | Representation |
---|---|
bin | 1010111001110011001101… |
… | …1001110100010111100011 |
3 | 1120110001102102110220211101 |
4 | 2232130303121310113203 |
5 | 3032403130212114001 |
6 | 41255133045255231 |
7 | 2345053456536013 |
oct | 256346331642743 |
9 | 46401372426741 |
10 | 11988116129251 |
11 | 390214a030919 |
12 | 1417463a04517 |
13 | 68c6226281c2 |
14 | 2d632958dc43 |
15 | 15bc8998da01 |
hex | ae7336745e3 |
11988116129251 has 2 divisors, whose sum is σ = 11988116129252. Its totient is φ = 11988116129250.
The previous prime is 11988116129219. The next prime is 11988116129267. The reversal of 11988116129251 is 15292161188911.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11988116129251 - 25 = 11988116129219 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11988116129192 and 11988116129201.
It is not a weakly prime, because it can be changed into another prime (11988116129551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5994058064625 + 5994058064626.
It is an arithmetic number, because the mean of its divisors is an integer number (5994058064626).
Almost surely, 211988116129251 is an apocalyptic number.
11988116129251 is a deficient number, since it is larger than the sum of its proper divisors (1).
11988116129251 is an equidigital number, since it uses as much as digits as its factorization.
11988116129251 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 622080, while the sum is 55.
The spelling of 11988116129251 in words is "eleven trillion, nine hundred eighty-eight billion, one hundred sixteen million, one hundred twenty-nine thousand, two hundred fifty-one".
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