Base | Representation |
---|---|
bin | 1010111001110011001101… |
… | …1001110100010111110011 |
3 | 1120110001102102110220211222 |
4 | 2232130303121310113303 |
5 | 3032403130212114032 |
6 | 41255133045255255 |
7 | 2345053456536035 |
oct | 256346331642763 |
9 | 46401372426758 |
10 | 11988116129267 |
11 | 390214a030933 |
12 | 1417463a0452b |
13 | 68c622628205 |
14 | 2d632958dc55 |
15 | 15bc8998da12 |
hex | ae7336745f3 |
11988116129267 has 2 divisors, whose sum is σ = 11988116129268. Its totient is φ = 11988116129266.
The previous prime is 11988116129251. The next prime is 11988116129309. The reversal of 11988116129267 is 76292161188911.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11988116129267 - 24 = 11988116129251 is a prime.
It is not a weakly prime, because it can be changed into another prime (11988116129467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5994058064633 + 5994058064634.
It is an arithmetic number, because the mean of its divisors is an integer number (5994058064634).
Almost surely, 211988116129267 is an apocalyptic number.
11988116129267 is a deficient number, since it is larger than the sum of its proper divisors (1).
11988116129267 is an equidigital number, since it uses as much as digits as its factorization.
11988116129267 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5225472, while the sum is 62.
The spelling of 11988116129267 in words is "eleven trillion, nine hundred eighty-eight billion, one hundred sixteen million, one hundred twenty-nine thousand, two hundred sixty-seven".
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