11988116129309 has 2 divisors, whose sum is σ = 11988116129310. Its totient is φ = 11988116129308.

The previous prime is 11988116129267. The next prime is 11988116129323. The reversal of 11988116129309 is 90392161188911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6665045805625 + 5323070323684 = 2581675^2 + 2307178^2 .

It is an emirp because it is prime and its reverse (90392161188911) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11988116129309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11988116129389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5994058064654 + 5994058064655.

It is an arithmetic number, because the mean of its divisors is an integer number (5994058064655).

Almost surely, 2^{11988116129309} is an apocalyptic number.

It is an amenable number.

11988116129309 is a deficient number, since it is larger than the sum of its proper divisors (1).

11988116129309 is an equidigital number, since it uses as much as digits as its factorization.

11988116129309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1679616, while the sum is 59.

The spelling of 11988116129309 in words is "eleven trillion, nine hundred eighty-eight billion, one hundred sixteen million, one hundred twenty-nine thousand, three hundred nine".