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119912584091 is a prime number
BaseRepresentation
bin110111110101101011…
…0001101001110011011
3102110111220200102102012
41233223112031032123
53431040110142331
6131030450500135
711443355101346
oct1575326151633
9373456612365
10119912584091
1146944589273
121b2a659464b
13b40005b691
145b378ad45d
1531bc48982b
hex1beb58d39b

119912584091 has 2 divisors, whose sum is σ = 119912584092. Its totient is φ = 119912584090.

The previous prime is 119912584073. The next prime is 119912584109. The reversal of 119912584091 is 190485219911.

It is a happy number.

Together with next prime (119912584109) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (119912584073) and next prime (119912584109).

It is a cyclic number.

It is not a de Polignac number, because 119912584091 - 226 = 119845475227 is a prime.

It is a super-2 number, since 2×1199125840912 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (119912584291) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59956292045 + 59956292046.

It is an arithmetic number, because the mean of its divisors is an integer number (59956292046).

Almost surely, 2119912584091 is an apocalyptic number.

119912584091 is a deficient number, since it is larger than the sum of its proper divisors (1).

119912584091 is an equidigital number, since it uses as much as digits as its factorization.

119912584091 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 233280, while the sum is 50.

The spelling of 119912584091 in words is "one hundred nineteen billion, nine hundred twelve million, five hundred eighty-four thousand, ninety-one".