Base | Representation |
---|---|
bin | 110111110101111100… |
… | …1100110010111010111 |
3 | 102110112120010210110021 |
4 | 1233223321212113113 |
5 | 3431044444041403 |
6 | 131031421410011 |
7 | 11443530003061 |
oct | 1575371462727 |
9 | 373476123407 |
10 | 119921862103 |
11 | 46949845a4a |
12 | 1b2a9709907 |
13 | b401c59724 |
14 | 5b38c06731 |
15 | 31bd1bd8bd |
hex | 1bebe665d7 |
119921862103 has 2 divisors, whose sum is σ = 119921862104. Its totient is φ = 119921862102.
The previous prime is 119921862101. The next prime is 119921862119. The reversal of 119921862103 is 301268129911.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 119921862103 - 21 = 119921862101 is a prime.
Together with 119921862101, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 119921862103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (119921862101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59960931051 + 59960931052.
It is an arithmetic number, because the mean of its divisors is an integer number (59960931052).
Almost surely, 2119921862103 is an apocalyptic number.
119921862103 is a deficient number, since it is larger than the sum of its proper divisors (1).
119921862103 is an equidigital number, since it uses as much as digits as its factorization.
119921862103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46656, while the sum is 43.
The spelling of 119921862103 in words is "one hundred nineteen billion, nine hundred twenty-one million, eight hundred sixty-two thousand, one hundred three".
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