11993568497257 has 2 divisors, whose sum is σ = 11993568497258. Its totient is φ = 11993568497256.

The previous prime is 11993568497227. The next prime is 11993568497333. The reversal of 11993568497257 is 75279486539911.

It is an a-pointer prime, because the next prime (11993568497333) can be obtained adding 11993568497257 to its sum of digits (76).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11390280752601 + 603287744656 = 3374949^2 + 776716^2 .

It is a cyclic number.

It is not a de Polignac number, because 11993568497257 - 2⁴³ = 3197475475049 is a prime.

It is not a weakly prime, because it can be changed into another prime (11993568497227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5996784248628 + 5996784248629.

It is an arithmetic number, because the mean of its divisors is an integer number (5996784248629).

Almost surely, 2^{11993568497257} is an apocalyptic number.

It is an amenable number.

11993568497257 is a deficient number, since it is larger than the sum of its proper divisors (1).

11993568497257 is an equidigital number, since it uses as much as digits as its factorization.

11993568497257 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1028764800, while the sum is 76.

The spelling of 11993568497257 in words is "eleven trillion, nine hundred ninety-three billion, five hundred sixty-eight million, four hundred ninety-seven thousand, two hundred fifty-seven".