11993568497333 has 2 divisors, whose sum is σ = 11993568497334. Its totient is φ = 11993568497332.

The previous prime is 11993568497257. The next prime is 11993568497353. The reversal of 11993568497333 is 33379486539911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8347580651524 + 3645987845809 = 2889218^2 + 1909447^2 .

It is a cyclic number.

It is not a de Polignac number, because 11993568497333 - 2²⁰ = 11993567448757 is a prime.

It is a super-2 number, since 2×11993568497333² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11993568497353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5996784248666 + 5996784248667.

It is an arithmetic number, because the mean of its divisors is an integer number (5996784248667).

Almost surely, 2^{11993568497333} is an apocalyptic number.

It is an amenable number.

11993568497333 is a deficient number, since it is larger than the sum of its proper divisors (1).

11993568497333 is an equidigital number, since it uses as much as digits as its factorization.

11993568497333 is an evil number, because the sum of its binary digits is even.

The product of its digits is 396809280, while the sum is 71.

The spelling of 11993568497333 in words is "eleven trillion, nine hundred ninety-three billion, five hundred sixty-eight million, four hundred ninety-seven thousand, three hundred thirty-three".