11993568497280 has 192 divisors, whose sum is σ = 42949191448800. Its totient is φ = 3198284891136.

The previous prime is 11993568497257. The next prime is 11993568497333. The reversal of 11993568497280 is 8279486539911.

11993568497280 is a `hidden beast` number, since 1 + 1 + 9 + 9 + 3 + 56 + 8 + 497 + 2 + 80 = 666.

It is a tau number, because it is divible by the number of its divisors (192).

It is a Smith number, since the sum of its digits (72) coincides with the sum of the digits of its prime factors.

It is a Harshad number since it is a multiple of its sum of digits (72).

It is a junction number, because it is equal to n+sod(n) for n = 11993568497199 and 11993568497208.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 38404050 + ... + 38715089.

It is a 2-persistent number, because it is pandigital, and so is 2⋅11993568497280 = 23987136994560, but 3⋅11993568497280 = 35980705491840 is not.

Almost surely, 2^{11993568497280} is an apocalyptic number.

11993568497280 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11993568497280 is an abundant number, since it is smaller than the sum of its proper divisors (30955622951520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11993568497280 is an frugal number, since it uses more digits than its factorization.

11993568497280 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77119173 (or 77119149 counting only the distinct ones).

The product of its (nonzero) digits is 235146240, while the sum is 72.

The spelling of 11993568497280 in words is "eleven trillion, nine hundred ninety-three billion, five hundred sixty-eight million, four hundred ninety-seven thousand, two hundred eighty".