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119936809050271 is a prime number
BaseRepresentation
bin11011010001010011110110…
…111001100010000010011111
3120201122211212102212012001221
4123101103312321202002133
5111210021041104102041
61103030113123314211
734156101636032053
oct3321236671420237
9521584772765057
10119936809050271
1135240a07a65414
121155068281b967
1351bccb987c465
142188d888a9c63
15dcec71be12d1
hex6d14f6e6209f

119936809050271 has 2 divisors, whose sum is σ = 119936809050272. Its totient is φ = 119936809050270.

The previous prime is 119936809050193. The next prime is 119936809050349. The reversal of 119936809050271 is 172050908639911.

It is a balanced prime because it is at equal distance from previous prime (119936809050193) and next prime (119936809050349).

It is a cyclic number.

It is not a de Polignac number, because 119936809050271 - 213 = 119936809042079 is a prime.

It is a super-2 number, since 2×1199368090502712 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119936809150271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59968404525135 + 59968404525136.

It is an arithmetic number, because the mean of its divisors is an integer number (59968404525136).

Almost surely, 2119936809050271 is an apocalyptic number.

119936809050271 is a deficient number, since it is larger than the sum of its proper divisors (1).

119936809050271 is an equidigital number, since it uses as much as digits as its factorization.

119936809050271 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7348320, while the sum is 61.

The spelling of 119936809050271 in words is "one hundred nineteen trillion, nine hundred thirty-six billion, eight hundred nine million, fifty thousand, two hundred seventy-one".