Base | Representation |
---|---|
bin | 11011010001010011110110… |
… | …111001100010000010011111 |
3 | 120201122211212102212012001221 |
4 | 123101103312321202002133 |
5 | 111210021041104102041 |
6 | 1103030113123314211 |
7 | 34156101636032053 |
oct | 3321236671420237 |
9 | 521584772765057 |
10 | 119936809050271 |
11 | 35240a07a65414 |
12 | 1155068281b967 |
13 | 51bccb987c465 |
14 | 2188d888a9c63 |
15 | dcec71be12d1 |
hex | 6d14f6e6209f |
119936809050271 has 2 divisors, whose sum is σ = 119936809050272. Its totient is φ = 119936809050270.
The previous prime is 119936809050193. The next prime is 119936809050349. The reversal of 119936809050271 is 172050908639911.
It is a balanced prime because it is at equal distance from previous prime (119936809050193) and next prime (119936809050349).
It is a cyclic number.
It is not a de Polignac number, because 119936809050271 - 213 = 119936809042079 is a prime.
It is a super-2 number, since 2×1199368090502712 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (119936809150271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59968404525135 + 59968404525136.
It is an arithmetic number, because the mean of its divisors is an integer number (59968404525136).
Almost surely, 2119936809050271 is an apocalyptic number.
119936809050271 is a deficient number, since it is larger than the sum of its proper divisors (1).
119936809050271 is an equidigital number, since it uses as much as digits as its factorization.
119936809050271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7348320, while the sum is 61.
The spelling of 119936809050271 in words is "one hundred nineteen trillion, nine hundred thirty-six billion, eight hundred nine million, fifty thousand, two hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •