Base | Representation |
---|---|
bin | 10110010101110001… |
… | …01000100010001101 |
3 | 1010221212102001210202 |
4 | 23022320220202031 |
5 | 144030401401232 |
6 | 5302044143245 |
7 | 603134301503 |
oct | 131270504215 |
9 | 33855361722 |
10 | 11993778317 |
11 | 50a51a2194 |
12 | 23a8837b25 |
13 | 1191a96961 |
14 | 81ac7c673 |
15 | 4a2e42162 |
hex | 2cae2888d |
11993778317 has 2 divisors, whose sum is σ = 11993778318. Its totient is φ = 11993778316.
The previous prime is 11993778241. The next prime is 11993778319. The reversal of 11993778317 is 71387739911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11553240196 + 440538121 = 107486^2 + 20989^2 .
It is a cyclic number.
It is not a de Polignac number, because 11993778317 - 28 = 11993778061 is a prime.
Together with 11993778319, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11993778319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5996889158 + 5996889159.
It is an arithmetic number, because the mean of its divisors is an integer number (5996889159).
Almost surely, 211993778317 is an apocalyptic number.
It is an amenable number.
11993778317 is a deficient number, since it is larger than the sum of its proper divisors (1).
11993778317 is an equidigital number, since it uses as much as digits as its factorization.
11993778317 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2000376, while the sum is 56.
The spelling of 11993778317 in words is "eleven billion, nine hundred ninety-three million, seven hundred seventy-eight thousand, three hundred seventeen".
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