Base | Representation |
---|---|
bin | 1110010011011… |
… | …00010100011101 |
3 | 22100202200110101 |
4 | 13021230110131 |
5 | 221203400331 |
6 | 15523341101 |
7 | 2654552554 |
oct | 711542435 |
9 | 270680411 |
10 | 119981341 |
11 | 617a9837 |
12 | 34221791 |
13 | 1bb1b59c |
14 | 11d12d9b |
15 | a800061 |
hex | 726c51d |
119981341 has 2 divisors, whose sum is σ = 119981342. Its totient is φ = 119981340.
The previous prime is 119981339. The next prime is 119981369. The reversal of 119981341 is 143189911.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 71470116 + 48511225 = 8454^2 + 6965^2 .
It is an emirp because it is prime and its reverse (143189911) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 119981341 - 21 = 119981339 is a prime.
Together with 119981339, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 119981341.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (119981311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59990670 + 59990671.
It is an arithmetic number, because the mean of its divisors is an integer number (59990671).
Almost surely, 2119981341 is an apocalyptic number.
It is an amenable number.
119981341 is a deficient number, since it is larger than the sum of its proper divisors (1).
119981341 is an equidigital number, since it uses as much as digits as its factorization.
119981341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7776, while the sum is 37.
The square root of 119981341 is about 10953.5994540608. The cubic root of 119981341 is about 493.2168485125.
The spelling of 119981341 in words is "one hundred nineteen million, nine hundred eighty-one thousand, three hundred forty-one".
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