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1200000988343 is a prime number
BaseRepresentation
bin10001011101100101101…
…000011111010010110111
311020201102010120022201202
4101131211220133102313
5124130100223111333
62315134533443115
7152461100050343
oct21354550372267
94221363508652
101200000988343
11422a10301703
12174699aa049b
138920c872821
144211a704623
1521334d335e8
hex11765a1f4b7

1200000988343 has 2 divisors, whose sum is σ = 1200000988344. Its totient is φ = 1200000988342.

The previous prime is 1200000988271. The next prime is 1200000988357. The reversal of 1200000988343 is 3438890000021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1200000988343 - 222 = 1199996794039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1200000988297 and 1200000988306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1200000888343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600000494171 + 600000494172.

It is an arithmetic number, because the mean of its divisors is an integer number (600000494172).

Almost surely, 21200000988343 is an apocalyptic number.

1200000988343 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200000988343 is an equidigital number, since it uses as much as digits as its factorization.

1200000988343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 38.

Adding to 1200000988343 its reverse (3438890000021), we get a palindrome (4638890988364).

The spelling of 1200000988343 in words is "one trillion, two hundred billion, nine hundred eighty-eight thousand, three hundred forty-three".