Base | Representation |
---|---|
bin | 1010111010011111100100… |
… | …0011000111010111010111 |
3 | 1120111012011011110212122102 |
4 | 2232213321003013113113 |
5 | 3033102021113013421 |
6 | 41304422313352315 |
7 | 2345654506014464 |
oct | 256477103072727 |
9 | 46435134425572 |
10 | 12000022001111 |
11 | 39071a9641641 |
12 | 141982710869b |
13 | 69079c123ab1 |
14 | 2d6b388a866b |
15 | 15c234d1960b |
hex | ae9f90c75d7 |
12000022001111 has 2 divisors, whose sum is σ = 12000022001112. Its totient is φ = 12000022001110.
The previous prime is 12000022001083. The next prime is 12000022001153. The reversal of 12000022001111 is 11110022000021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12000022001111 is a prime.
It is a super-3 number, since 3×120000220011113 (a number of 40 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 12000022001092 and 12000022001101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12000022001711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000011000555 + 6000011000556.
It is an arithmetic number, because the mean of its divisors is an integer number (6000011000556).
Almost surely, 212000022001111 is an apocalyptic number.
12000022001111 is a deficient number, since it is larger than the sum of its proper divisors (1).
12000022001111 is an equidigital number, since it uses as much as digits as its factorization.
12000022001111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 12000022001111 its reverse (11110022000021), we get a palindrome (23110044001132).
The spelling of 12000022001111 in words is "twelve trillion, twenty-two million, one thousand, one hundred eleven".
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