Search a number
-
+
12000022001153 is a prime number
BaseRepresentation
bin1010111010011111100100…
…0011000111011000000001
31120111012011011110212200222
42232213321003013120001
53033102021113014103
641304422313352425
72345654506014554
oct256477103073001
946435134425628
1012000022001153
1139071a964167a
121419827108715
1369079c123b14
142d6b388a869b
1515c234d19638
hexae9f90c7601

12000022001153 has 2 divisors, whose sum is σ = 12000022001154. Its totient is φ = 12000022001152.

The previous prime is 12000022001111. The next prime is 12000022001183. The reversal of 12000022001153 is 35110022000021.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9716486968384 + 2283535032769 = 3117128^2 + 1511137^2 .

It is a cyclic number.

It is not a de Polignac number, because 12000022001153 - 216 = 12000021935617 is a prime.

It is not a weakly prime, because it can be changed into another prime (12000022001183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000011000576 + 6000011000577.

It is an arithmetic number, because the mean of its divisors is an integer number (6000011000577).

Almost surely, 212000022001153 is an apocalyptic number.

It is an amenable number.

12000022001153 is a deficient number, since it is larger than the sum of its proper divisors (1).

12000022001153 is an equidigital number, since it uses as much as digits as its factorization.

12000022001153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 17.

Adding to 12000022001153 its reverse (35110022000021), we get a palindrome (47110044001174).

The spelling of 12000022001153 in words is "twelve trillion, twenty-two million, one thousand, one hundred fifty-three".