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120000491953 is a prime number
BaseRepresentation
bin110111111000010010…
…1100011000110110001
3102110202001002121022221
41233300211203012301
53431230111220303
6131043311001041
711445503231446
oct1576045430661
9373661077287
10120000491953
114698a1707a1
121b30bb09181
13b41532a274
145b454339cd
1531c50514bd
hex1bf09631b1

120000491953 has 2 divisors, whose sum is σ = 120000491954. Its totient is φ = 120000491952.

The previous prime is 120000491929. The next prime is 120000491977. The reversal of 120000491953 is 359194000021.

It is a balanced prime because it is at equal distance from previous prime (120000491929) and next prime (120000491977).

It can be written as a sum of positive squares in only one way, i.e., 95922142369 + 24078349584 = 309713^2 + 155172^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120000491953 is a prime.

It is not a weakly prime, because it can be changed into another prime (120000491903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60000245976 + 60000245977.

It is an arithmetic number, because the mean of its divisors is an integer number (60000245977).

Almost surely, 2120000491953 is an apocalyptic number.

It is an amenable number.

120000491953 is a deficient number, since it is larger than the sum of its proper divisors (1).

120000491953 is an equidigital number, since it uses as much as digits as its factorization.

120000491953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9720, while the sum is 34.

Adding to 120000491953 its reverse (359194000021), we get a palindrome (479194491974).

The spelling of 120000491953 in words is "one hundred twenty billion, four hundred ninety-one thousand, nine hundred fifty-three".