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1200010010112 = 2932374125379
BaseRepresentation
bin10001011101100110001…
…010111001111000000000
311020201102202112200021100
4101131212022321320000
5124130110030310422
62315135455054400
7152461236534024
oct21354612717000
94221382480240
101200010010112
11422a15403911
121746a0b11400
13892116b1054
144211b9b2384
1521335a167ac
hex117662b9e00

1200010010112 has 720 divisors, whose sum is σ = 3761591296320. Its totient is φ = 367820144640.

The previous prime is 1200010010083. The next prime is 1200010010113. The reversal of 1200010010112 is 2110100100021.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a junction number, because it is equal to n+sod(n) for n = 1200010010094 and 1200010010103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200010010113) by changing a digit.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 15190000089 + ... + 15190000167.

It is an arithmetic number, because the mean of its divisors is an integer number (5224432356).

Almost surely, 21200010010112 is an apocalyptic number.

1200010010112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1200010010112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1880795648160).

1200010010112 is an abundant number, since it is smaller than the sum of its proper divisors (2561581286208).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1200010010112 is an equidigital number, since it uses as much as digits as its factorization.

1200010010112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 275 (or 215 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 9.

Adding to 1200010010112 its reverse (2110100100021), we get a palindrome (3310110110133).

The spelling of 1200010010112 in words is "one trillion, two hundred billion, ten million, ten thousand, one hundred twelve".