Base | Representation |
---|---|
bin | 11011010010001111101111… |
… | …000100100001001010110111 |
3 | 120201212222211010210201021202 |
4 | 123102033233010201022313 |
5 | 111212044224132101012 |
6 | 1103115424553203115 |
7 | 34163536116003326 |
oct | 3322175704411267 |
9 | 521788733721252 |
10 | 120001102222007 |
11 | 352661aa866996 |
12 | 1156102640049b |
13 | 51c60948a7b46 |
14 | 218c1275ca0bd |
15 | dd17862c9cc2 |
hex | 6d23ef1212b7 |
120001102222007 has 2 divisors, whose sum is σ = 120001102222008. Its totient is φ = 120001102222006.
The previous prime is 120001102221977. The next prime is 120001102222009. The reversal of 120001102222007 is 700222201100021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120001102222007 - 28 = 120001102221751 is a prime.
Together with 120001102222009, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 120001102222007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120001102222009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60000551111003 + 60000551111004.
It is an arithmetic number, because the mean of its divisors is an integer number (60000551111004).
Almost surely, 2120001102222007 is an apocalyptic number.
120001102222007 is a deficient number, since it is larger than the sum of its proper divisors (1).
120001102222007 is an equidigital number, since it uses as much as digits as its factorization.
120001102222007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 20.
Adding to 120001102222007 its reverse (700222201100021), we get a palindrome (820223303322028).
The spelling of 120001102222007 in words is "one hundred twenty trillion, one billion, one hundred two million, two hundred twenty-two thousand, seven".
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