1200012103111 has 2 divisors, whose sum is σ = 1200012103112. Its totient is φ = 1200012103110.

The previous prime is 1200012103093. The next prime is 1200012103127. The reversal of 1200012103111 is 1113012100021.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (1113012100021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1200012103111 - 2¹¹ = 1200012101063 is a prime.

It is a super-2 number, since 2×1200012103111² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1200012103091 and 1200012103100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1200012104111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600006051555 + 600006051556.

It is an arithmetic number, because the mean of its divisors is an integer number (600006051556).

Almost surely, 2^{1200012103111} is an apocalyptic number.

1200012103111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200012103111 is an equidigital number, since it uses as much as digits as its factorization.

1200012103111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1200012103111 its reverse (1113012100021), we get a palindrome (2313024203132).

The spelling of 1200012103111 in words is "one trillion, two hundred billion, twelve million, one hundred three thousand, one hundred eleven".