Base | Representation |
---|---|
bin | 1010111010011111111011… |
… | …1101100111100010000111 |
3 | 1120111012102002011212220102 |
4 | 2232213332331213202013 |
5 | 3033102222013121203 |
6 | 41304440220154315 |
7 | 2345660122260143 |
oct | 256477675474207 |
9 | 46435362155812 |
10 | 12000121223303 |
11 | 390724a651754 |
12 | 141985439899b |
13 | 6907b6854555 |
14 | 2d6b47b36223 |
15 | 15c23d8b8888 |
hex | ae9fef67887 |
12000121223303 has 2 divisors, whose sum is σ = 12000121223304. Its totient is φ = 12000121223302.
The previous prime is 12000121223297. The next prime is 12000121223309. The reversal of 12000121223303 is 30332212100021.
It is a balanced prime because it is at equal distance from previous prime (12000121223297) and next prime (12000121223309).
It is a cyclic number.
It is not a de Polignac number, because 12000121223303 - 24 = 12000121223287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12000121223309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000060611651 + 6000060611652.
It is an arithmetic number, because the mean of its divisors is an integer number (6000060611652).
Almost surely, 212000121223303 is an apocalyptic number.
12000121223303 is a deficient number, since it is larger than the sum of its proper divisors (1).
12000121223303 is an equidigital number, since it uses as much as digits as its factorization.
12000121223303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 12000121223303 its reverse (30332212100021), we get a palindrome (42332333323324).
The spelling of 12000121223303 in words is "twelve trillion, one hundred twenty-one million, two hundred twenty-three thousand, three hundred three".
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