Base | Representation |
---|---|
bin | 1010111010011111111100… |
… | …0001000010111101111111 |
3 | 1120111012102010212112211121 |
4 | 2232213333001002331333 |
5 | 3033102222230401421 |
6 | 41304440251331411 |
7 | 2345660133022444 |
oct | 256477701027577 |
9 | 46435363775747 |
10 | 12000122122111 |
11 | 3907250105a72 |
12 | 1419854750b67 |
13 | 6907b6aaa6a6 |
14 | 2d6b47ccb9cb |
15 | 15c23d9e4d41 |
hex | ae9ff042f7f |
12000122122111 has 2 divisors, whose sum is σ = 12000122122112. Its totient is φ = 12000122122110.
The previous prime is 12000122122099. The next prime is 12000122122117. The reversal of 12000122122111 is 11122122100021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12000122122111 - 213 = 12000122113919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12000122122117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000061061055 + 6000061061056.
It is an arithmetic number, because the mean of its divisors is an integer number (6000061061056).
Almost surely, 212000122122111 is an apocalyptic number.
12000122122111 is a deficient number, since it is larger than the sum of its proper divisors (1).
12000122122111 is an equidigital number, since it uses as much as digits as its factorization.
12000122122111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 12000122122111 its reverse (11122122100021), we get a palindrome (23122244222132).
The spelling of 12000122122111 in words is "twelve trillion, one hundred twenty-two million, one hundred twenty-two thousand, one hundred eleven".
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