Base | Representation |
---|---|
bin | 11011010010010000100101… |
… | …010011110011110010111011 |
3 | 120201220002011120002101120221 |
4 | 123102100211103303302323 |
5 | 111212103110110400443 |
6 | 1103120055141200511 |
7 | 34163600505460624 |
oct | 3322204523636273 |
9 | 521802146071527 |
10 | 120002012200123 |
11 | 35266627493a19 |
12 | 1156123b100137 |
13 | 51c61ab286131 |
14 | 218c1b23c2a4b |
15 | dd17db127eed |
hex | 6d24254f3cbb |
120002012200123 has 2 divisors, whose sum is σ = 120002012200124. Its totient is φ = 120002012200122.
The previous prime is 120002012200043. The next prime is 120002012200129. The reversal of 120002012200123 is 321002210200021.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120002012200123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 120002012200097 and 120002012200106.
It is not a weakly prime, because it can be changed into another prime (120002012200129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60001006100061 + 60001006100062.
It is an arithmetic number, because the mean of its divisors is an integer number (60001006100062).
Almost surely, 2120002012200123 is an apocalyptic number.
120002012200123 is a deficient number, since it is larger than the sum of its proper divisors (1).
120002012200123 is an equidigital number, since it uses as much as digits as its factorization.
120002012200123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 120002012200123 its reverse (321002210200021), we get a palindrome (441004222400144).
The spelling of 120002012200123 in words is "one hundred twenty trillion, two billion, twelve million, two hundred thousand, one hundred twenty-three".
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