Search a number
-
+
120002110122157 is a prime number
BaseRepresentation
bin11011010010010000101011…
…001001010110100010101101
3120201220002102101100100100221
4123102100223021112202231
5111212103310142402112
61103120113000051341
734163603105006614
oct3322205311264255
9521802371310327
10120002110122157
113526667779621a
1211561267a63b51
1351c61c564cb73
14218c1c13d287b
15dd17e4a1be07
hex6d242b2568ad

120002110122157 has 2 divisors, whose sum is σ = 120002110122158. Its totient is φ = 120002110122156.

The previous prime is 120002110122151. The next prime is 120002110122253. The reversal of 120002110122157 is 751221011200021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94055199618436 + 25946910503721 = 9698206^2 + 5093811^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120002110122157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120002110122151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60001055061078 + 60001055061079.

It is an arithmetic number, because the mean of its divisors is an integer number (60001055061079).

Almost surely, 2120002110122157 is an apocalyptic number.

It is an amenable number.

120002110122157 is a deficient number, since it is larger than the sum of its proper divisors (1).

120002110122157 is an equidigital number, since it uses as much as digits as its factorization.

120002110122157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 560, while the sum is 25.

Adding to 120002110122157 its reverse (751221011200021), we get a palindrome (871223121322178).

The spelling of 120002110122157 in words is "one hundred twenty trillion, two billion, one hundred ten million, one hundred twenty-two thousand, one hundred fifty-seven".