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12000332493400 = 2352536722937369
BaseRepresentation
bin1010111010100000101110…
…0011100011001001011000
31120111012221210201111222211
42232220023203203021120
53033103140104242100
641304513204324504
72345665266114016
oct256501343431130
946435853644884
1012000332493400
113907348932039
1214198b30a3734
1369081b556544
142d6b67c0d8b6
1515c2521ec1ba
hexaea0b8e3258

12000332493400 has 192 divisors, whose sum is σ = 28867988714400. Its totient is φ = 4636619919360.

The previous prime is 12000332493367. The next prime is 12000332493419. The reversal of 12000332493400 is 439423300021.

It is a super-2 number, since 2×120003324934002 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1628484916 + ... + 1628492284.

Almost surely, 212000332493400 is an apocalyptic number.

12000332493400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12000332493400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14433994357200).

12000332493400 is an abundant number, since it is smaller than the sum of its proper divisors (16867656221000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12000332493400 is a wasteful number, since it uses less digits than its factorization.

12000332493400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9798 (or 9789 counting only the distinct ones).

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 12000332493400 its reverse (439423300021), we get a palindrome (12439755793421).

The spelling of 12000332493400 in words is "twelve trillion, three hundred thirty-two million, four hundred ninety-three thousand, four hundred".