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1200040042303 is a prime number
BaseRepresentation
bin10001011101100111111…
…101011101111100111111
311020201111212001110200201
4101131213331131330333
5124130140222323203
62315142450504331
7152462053025314
oct21354775357477
94221455043621
101200040042303
11422a30356503
121746aab950a7
138921799788b
144212198cd0b
1521338499e1d
hex11767f5df3f

1200040042303 has 2 divisors, whose sum is σ = 1200040042304. Its totient is φ = 1200040042302.

The previous prime is 1200040042301. The next prime is 1200040042337. The reversal of 1200040042303 is 3032400400021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1200040042303 - 21 = 1200040042301 is a prime.

It is a super-2 number, since 2×12000400423032 (a number of 25 digits) contains 22 as substring.

Together with 1200040042301, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1200040042301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600020021151 + 600020021152.

It is an arithmetic number, because the mean of its divisors is an integer number (600020021152).

Almost surely, 21200040042303 is an apocalyptic number.

1200040042303 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200040042303 is an equidigital number, since it uses as much as digits as its factorization.

1200040042303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 19.

Adding to 1200040042303 its reverse (3032400400021), we get a palindrome (4232440442324).

The spelling of 1200040042303 in words is "one trillion, two hundred billion, forty million, forty-two thousand, three hundred three".