Base | Representation |
---|---|
bin | 1010111010100011001101… |
… | …1010001000000101011111 |
3 | 1120111021200101211212011002 |
4 | 2232220303122020011133 |
5 | 3033111022241040103 |
6 | 41305103411220515 |
7 | 2346020665224056 |
oct | 256506332100537 |
9 | 46437611755132 |
10 | 12001001111903 |
11 | 3907661298011 |
12 | 1419a5aba773b |
13 | 6908c6c28bab |
14 | 2d6bcc93939d |
15 | 15c290c71488 |
hex | aea3368815f |
12001001111903 has 2 divisors, whose sum is σ = 12001001111904. Its totient is φ = 12001001111902.
The previous prime is 12001001111861. The next prime is 12001001112019. The reversal of 12001001111903 is 30911110010021.
It is a happy number.
12001001111903 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12001001111903 - 28 = 12001001111647 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12001001113903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000500555951 + 6000500555952.
It is an arithmetic number, because the mean of its divisors is an integer number (6000500555952).
Almost surely, 212001001111903 is an apocalyptic number.
12001001111903 is a deficient number, since it is larger than the sum of its proper divisors (1).
12001001111903 is an equidigital number, since it uses as much as digits as its factorization.
12001001111903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 20.
Adding to 12001001111903 its reverse (30911110010021), we get a palindrome (42912111121924).
The spelling of 12001001111903 in words is "twelve trillion, one billion, one million, one hundred eleven thousand, nine hundred three".
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