Base | Representation |
---|---|
bin | 10001011101101100001… |
… | …100111111100110110011 |
3 | 11020201200210222201202002 |
4 | 101131230030333212303 |
5 | 124130311433034141 |
6 | 2315153512244215 |
7 | 152463606032012 |
oct | 21355414774663 |
9 | 4221623881662 |
10 | 1200111221171 |
11 | 422a67552215 |
12 | 17470a9a066b |
13 | 89229659b55 |
14 | 4212b1daa79 |
15 | 2133e859e9b |
hex | 1176c33f9b3 |
1200111221171 has 2 divisors, whose sum is σ = 1200111221172. Its totient is φ = 1200111221170.
The previous prime is 1200111221123. The next prime is 1200111221173. The reversal of 1200111221171 is 1711221110021.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1200111221171 - 230 = 1199037479347 is a prime.
It is a super-3 number, since 3×12001112211713 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 1200111221173, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1200111221173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600055610585 + 600055610586.
It is an arithmetic number, because the mean of its divisors is an integer number (600055610586).
Almost surely, 21200111221171 is an apocalyptic number.
1200111221171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200111221171 is an equidigital number, since it uses as much as digits as its factorization.
1200111221171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 1200111221171 its reverse (1711221110021), we get a palindrome (2911332331192).
The spelling of 1200111221171 in words is "one trillion, two hundred billion, one hundred eleven million, two hundred twenty-one thousand, one hundred seventy-one".
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