Base | Representation |
---|---|
bin | 10001011101101100110… |
… | …110001100100011110011 |
3 | 11020201201120022110212122 |
4 | 101131230312030203303 |
5 | 124130322214202011 |
6 | 2315154535544455 |
7 | 152464066605464 |
oct | 21355466144363 |
9 | 4221646273778 |
10 | 1200122022131 |
11 | 422a7265a12a |
12 | 17471252b12b |
13 | 8922b96c156 |
14 | 4212c80cd6b |
15 | 213407903db |
hex | 1176cd8c8f3 |
1200122022131 has 2 divisors, whose sum is σ = 1200122022132. Its totient is φ = 1200122022130.
The previous prime is 1200122022089. The next prime is 1200122022133. The reversal of 1200122022131 is 1312202210021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1200122022131 is a prime.
It is a super-2 number, since 2×12001220221312 (a number of 25 digits) contains 22 as substring.
Together with 1200122022133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1200122022133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600061011065 + 600061011066.
It is an arithmetic number, because the mean of its divisors is an integer number (600061011066).
Almost surely, 21200122022131 is an apocalyptic number.
1200122022131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200122022131 is an equidigital number, since it uses as much as digits as its factorization.
1200122022131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 1200122022131 its reverse (1312202210021), we get a palindrome (2512324232152).
The spelling of 1200122022131 in words is "one trillion, two hundred billion, one hundred twenty-two million, twenty-two thousand, one hundred thirty-one".
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