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12001322220127 is a prime number
BaseRepresentation
bin1010111010100100011010…
…0011000011101001011111
31120111022111210001211211021
42232221012203003221133
53033112201442021002
641305155321505011
72346031644466462
oct256510643035137
946438453054737
1012001322220127
113907806579409
121419b2a642167
13690948607666
142d6c1d4452d9
1515c2ae04e737
hexaea468c3a5f

12001322220127 has 2 divisors, whose sum is σ = 12001322220128. Its totient is φ = 12001322220126.

The previous prime is 12001322220061. The next prime is 12001322220133. The reversal of 12001322220127 is 72102222310021.

It is a strong prime.

It is an emirp because it is prime and its reverse (72102222310021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12001322220127 is a prime.

It is a super-2 number, since 2×120013222201272 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12001322220227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000661110063 + 6000661110064.

It is an arithmetic number, because the mean of its divisors is an integer number (6000661110064).

Almost surely, 212001322220127 is an apocalyptic number.

12001322220127 is a deficient number, since it is larger than the sum of its proper divisors (1).

12001322220127 is an equidigital number, since it uses as much as digits as its factorization.

12001322220127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 25.

Adding to 12001322220127 its reverse (72102222310021), we get a palindrome (84103544530148).

The spelling of 12001322220127 in words is "twelve trillion, one billion, three hundred twenty-two million, two hundred twenty thousand, one hundred twenty-seven".