Base | Representation |
---|---|
bin | 11011010010100010010111… |
… | …110100110001010000001011 |
3 | 120201221220110202012102111212 |
4 | 123102202113310301100023 |
5 | 111212411220001443032 |
6 | 1103132534400243335 |
7 | 34165145034320336 |
oct | 3322422764612013 |
9 | 521856422172455 |
10 | 120021113312267 |
11 | 35273739580212 |
12 | 11564a9001054b |
13 | 51c7c3366665b |
14 | 218d0a515b61d |
15 | dd2057ed6bb2 |
hex | 6d2897d3140b |
120021113312267 has 2 divisors, whose sum is σ = 120021113312268. Its totient is φ = 120021113312266.
The previous prime is 120021113312173. The next prime is 120021113312279. The reversal of 120021113312267 is 762213311120021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120021113312267 - 218 = 120021113050123 is a prime.
It is not a weakly prime, because it can be changed into another prime (120021113312297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60010556656133 + 60010556656134.
It is an arithmetic number, because the mean of its divisors is an integer number (60010556656134).
Almost surely, 2120021113312267 is an apocalyptic number.
120021113312267 is a deficient number, since it is larger than the sum of its proper divisors (1).
120021113312267 is an equidigital number, since it uses as much as digits as its factorization.
120021113312267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 32.
Adding to 120021113312267 its reverse (762213311120021), we get a palindrome (882234424432288).
The spelling of 120021113312267 in words is "one hundred twenty trillion, twenty-one billion, one hundred thirteen million, three hundred twelve thousand, two hundred sixty-seven".
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