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120021113312173 is a prime number
BaseRepresentation
bin11011010010100010010111…
…110100110001001110101101
3120201221220110202012102101101
4123102202113310301032231
5111212411220001442143
61103132534400243101
734165145034320143
oct3322422764611655
9521856422172341
10120021113312173
1135273739580137
1211564a90010491
1351c7c336665b8
14218d0a515b593
15dd2057ed6b4d
hex6d2897d313ad

120021113312173 has 2 divisors, whose sum is σ = 120021113312174. Its totient is φ = 120021113312172.

The previous prime is 120021113312171. The next prime is 120021113312267. The reversal of 120021113312173 is 371213311120021.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120006284648644 + 14828663529 = 10954738^2 + 121773^2 .

It is a cyclic number.

It is not a de Polignac number, because 120021113312173 - 21 = 120021113312171 is a prime.

Together with 120021113312171, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120021113312171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60010556656086 + 60010556656087.

It is an arithmetic number, because the mean of its divisors is an integer number (60010556656087).

Almost surely, 2120021113312173 is an apocalyptic number.

It is an amenable number.

120021113312173 is a deficient number, since it is larger than the sum of its proper divisors (1).

120021113312173 is an equidigital number, since it uses as much as digits as its factorization.

120021113312173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 28.

Adding to 120021113312173 its reverse (371213311120021), we get a palindrome (491234424432194).

The spelling of 120021113312173 in words is "one hundred twenty trillion, twenty-one billion, one hundred thirteen million, three hundred twelve thousand, one hundred seventy-three".