Base | Representation |
---|---|
bin | 11011010010100010011101… |
… | …110001100000011101001010 |
3 | 120201221220201201000012102210 |
4 | 123102202131301200131022 |
5 | 111212411421024322310 |
6 | 1103132552323405550 |
7 | 34165150355553054 |
oct | 3322423561403512 |
9 | 521856651005383 |
10 | 120021213120330 |
11 | 3527378a950515 |
12 | 11564ab95238b6 |
13 | 51c7c4b240992 |
14 | 218d0b44dc8d4 |
15 | dd2061b4e820 |
hex | 6d289dc6074a |
120021213120330 has 32 divisors (see below), whose sum is σ = 288069536182464. Its totient is φ = 32003587421696.
The previous prime is 120021213120293. The next prime is 120021213120383. The reversal of 120021213120330 is 33021312120021.
It is a junction number, because it is equal to n+sod(n) for n = 120021213120297 and 120021213120306.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 128866407 + ... + 129794426.
It is an arithmetic number, because the mean of its divisors is an integer number (9002173005702).
Almost surely, 2120021213120330 is an apocalyptic number.
120021213120330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
120021213120330 is an abundant number, since it is smaller than the sum of its proper divisors (168048323062134).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120021213120330 is a wasteful number, since it uses less digits than its factorization.
120021213120330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 258676310.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 120021213120330 its reverse (33021312120021), we get a palindrome (153042525240351).
The spelling of 120021213120330 in words is "one hundred twenty trillion, twenty-one billion, two hundred thirteen million, one hundred twenty thousand, three hundred thirty".
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