Base | Representation |
---|---|
bin | 1010111010100111011011… |
… | …0000101111010101111101 |
3 | 1120111101121011010212201012 |
4 | 2232221312300233111331 |
5 | 3033120331031111331 |
6 | 41305411455125005 |
7 | 2346060666122645 |
oct | 256516660572575 |
9 | 46441534125635 |
10 | 12002131113341 |
11 | 39080911338a6 |
12 | 141a115513765 |
13 | 690a470823b5 |
14 | 2d6c98a47525 |
15 | 15c30a08182b |
hex | aea76c2f57d |
12002131113341 has 2 divisors, whose sum is σ = 12002131113342. Its totient is φ = 12002131113340.
The previous prime is 12002131113319. The next prime is 12002131113373. The reversal of 12002131113341 is 14331113120021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11084072025625 + 918059087716 = 3329275^2 + 958154^2 .
It is a cyclic number.
It is not a de Polignac number, because 12002131113341 - 238 = 11727253206397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12002131115341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001065556670 + 6001065556671.
It is an arithmetic number, because the mean of its divisors is an integer number (6001065556671).
Almost surely, 212002131113341 is an apocalyptic number.
It is an amenable number.
12002131113341 is a deficient number, since it is larger than the sum of its proper divisors (1).
12002131113341 is an equidigital number, since it uses as much as digits as its factorization.
12002131113341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 12002131113341 its reverse (14331113120021), we get a palindrome (26333244233362).
The spelling of 12002131113341 in words is "twelve trillion, two billion, one hundred thirty-one million, one hundred thirteen thousand, three hundred forty-one".
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