Base | Representation |
---|---|
bin | 1010111010100111011011… |
… | …0000101111010101100111 |
3 | 1120111101121011010212200101 |
4 | 2232221312300233111213 |
5 | 3033120331031111234 |
6 | 41305411455124531 |
7 | 2346060666122614 |
oct | 256516660572547 |
9 | 46441534125611 |
10 | 12002131113319 |
11 | 3908091133886 |
12 | 141a115513747 |
13 | 690a47082399 |
14 | 2d6c98a4750b |
15 | 15c30a081814 |
hex | aea76c2f567 |
12002131113319 has 2 divisors, whose sum is σ = 12002131113320. Its totient is φ = 12002131113318.
The previous prime is 12002131113317. The next prime is 12002131113341. The reversal of 12002131113319 is 91331113120021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12002131113319 - 21 = 12002131113317 is a prime.
It is a super-2 number, since 2×120021311133192 (a number of 27 digits) contains 22 as substring.
Together with 12002131113317, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12002131113317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001065556659 + 6001065556660.
It is an arithmetic number, because the mean of its divisors is an integer number (6001065556660).
Almost surely, 212002131113319 is an apocalyptic number.
12002131113319 is a deficient number, since it is larger than the sum of its proper divisors (1).
12002131113319 is an equidigital number, since it uses as much as digits as its factorization.
12002131113319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 28.
The spelling of 12002131113319 in words is "twelve trillion, two billion, one hundred thirty-one million, one hundred thirteen thousand, three hundred nineteen".
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