Base | Representation |
---|---|
bin | 11011010010100011001101… |
… | …011001011101010000001111 |
3 | 120201221222210101110200211221 |
4 | 123102203031121131100033 |
5 | 111212420040100402002 |
6 | 1103133203505024211 |
7 | 34165206230141263 |
oct | 3322431531352017 |
9 | 521858711420757 |
10 | 120022012122127 |
11 | 3527405a96a385 |
12 | 115650a1025067 |
13 | 51c80479343cb |
14 | 218d14c6880a3 |
15 | dd20abd7ac37 |
hex | 6d28cd65d40f |
120022012122127 has 2 divisors, whose sum is σ = 120022012122128. Its totient is φ = 120022012122126.
The previous prime is 120022012122109. The next prime is 120022012122203. The reversal of 120022012122127 is 721221210220021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120022012122127 - 215 = 120022012089359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120022012122527) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60011006061063 + 60011006061064.
It is an arithmetic number, because the mean of its divisors is an integer number (60011006061064).
Almost surely, 2120022012122127 is an apocalyptic number.
120022012122127 is a deficient number, since it is larger than the sum of its proper divisors (1).
120022012122127 is an equidigital number, since it uses as much as digits as its factorization.
120022012122127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 120022012122127 its reverse (721221210220021), we get a palindrome (841243222342148).
The spelling of 120022012122127 in words is "one hundred twenty trillion, twenty-two billion, twelve million, one hundred twenty-two thousand, one hundred twenty-seven".
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