Base | Representation |
---|---|
bin | 1010111010101000000110… |
… | …0011110101100011000111 |
3 | 1120111102001210001010000012 |
4 | 2232222001203311203013 |
5 | 3033121213420432023 |
6 | 41305441450140435 |
7 | 2346065326041254 |
oct | 256520143654307 |
9 | 46442053033005 |
10 | 12002312280263 |
11 | 3908174423228 |
12 | 141a16612171b |
13 | 690a75774466 |
14 | 2d6cb4b2642b |
15 | 15c31ae1a978 |
hex | aea818f58c7 |
12002312280263 has 2 divisors, whose sum is σ = 12002312280264. Its totient is φ = 12002312280262.
The previous prime is 12002312280247. The next prime is 12002312280307. The reversal of 12002312280263 is 36208221320021.
12002312280263 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (36208221320021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12002312280263 - 24 = 12002312280247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12002312282263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001156140131 + 6001156140132.
It is an arithmetic number, because the mean of its divisors is an integer number (6001156140132).
Almost surely, 212002312280263 is an apocalyptic number.
12002312280263 is a deficient number, since it is larger than the sum of its proper divisors (1).
12002312280263 is an equidigital number, since it uses as much as digits as its factorization.
12002312280263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 32.
The spelling of 12002312280263 in words is "twelve trillion, two billion, three hundred twelve million, two hundred eighty thousand, two hundred sixty-three".
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