12003321033131 has 2 divisors, whose sum is σ = 12003321033132. Its totient is φ = 12003321033130.

The previous prime is 12003321033113. The next prime is 12003321033133. The reversal of 12003321033131 is 13133012330021.

Together with previous prime (12003321033113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12003321033131 - 2¹⁴ = 12003321016747 is a prime.

It is a super-2 number, since 2×12003321033131² (a number of 27 digits) contains 22 as substring.

Together with 12003321033133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12003321033097 and 12003321033106.

It is not a weakly prime, because it can be changed into another prime (12003321033133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001660516565 + 6001660516566.

It is an arithmetic number, because the mean of its divisors is an integer number (6001660516566).

Almost surely, 2^{12003321033131} is an apocalyptic number.

12003321033131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12003321033131 is an equidigital number, since it uses as much as digits as its factorization.

12003321033131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 12003321033131 its reverse (13133012330021), we get a palindrome (25136333363152).

The spelling of 12003321033131 in words is "twelve trillion, three billion, three hundred twenty-one million, thirty-three thousand, one hundred thirty-one".