120034344034013 has 2 divisors, whose sum is σ = 120034344034014. Its totient is φ = 120034344034012.

The previous prime is 120034344033887. The next prime is 120034344034103. The reversal of 120034344034013 is 310430443430021.

Together with next prime (120034344034103) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86651579194489 + 33382764839524 = 9308683^2 + 5777782^2 .

It is a cyclic number.

It is not a de Polignac number, because 120034344034013 - 2⁸ = 120034344033757 is a prime.

It is a super-2 number, since 2×120034344034013² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120034344031013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60017172017006 + 60017172017007.

It is an arithmetic number, because the mean of its divisors is an integer number (60017172017007).

Almost surely, 2^{120034344034013} is an apocalyptic number.

It is an amenable number.

120034344034013 is a deficient number, since it is larger than the sum of its proper divisors (1).

120034344034013 is an equidigital number, since it uses as much as digits as its factorization.

120034344034013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 120034344034013 its reverse (310430443430021), we get a palindrome (430464787464034).

The spelling of 120034344034013 in words is "one hundred twenty trillion, thirty-four billion, three hundred forty-four million, thirty-four thousand, thirteen".