Base | Representation |
---|---|
bin | 10110010111011110… |
… | …10100000110000101 |
3 | 1010222212101022122001 |
4 | 23023233110012011 |
5 | 144043034100032 |
6 | 5303315305301 |
7 | 603400162252 |
oct | 131357240605 |
9 | 33885338561 |
10 | 12008112517 |
11 | 51022a2735 |
12 | 23b15ab231 |
13 | 1194a4522b |
14 | 81cb30429 |
15 | 4a43243e7 |
hex | 2cbbd4185 |
12008112517 has 2 divisors, whose sum is σ = 12008112518. Its totient is φ = 12008112516.
The previous prime is 12008112449. The next prime is 12008112541. The reversal of 12008112517 is 71521180021.
12008112517 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7620242436 + 4387870081 = 87294^2 + 66241^2 .
It is a cyclic number.
It is not a de Polignac number, because 12008112517 - 215 = 12008079749 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12008116517) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6004056258 + 6004056259.
It is an arithmetic number, because the mean of its divisors is an integer number (6004056259).
Almost surely, 212008112517 is an apocalyptic number.
It is an amenable number.
12008112517 is a deficient number, since it is larger than the sum of its proper divisors (1).
12008112517 is an equidigital number, since it uses as much as digits as its factorization.
12008112517 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1120, while the sum is 28.
Adding to 12008112517 its reverse (71521180021), we get a palindrome (83529292538).
The spelling of 12008112517 in words is "twelve billion, eight million, one hundred twelve thousand, five hundred seventeen".
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