Base | Representation |
---|---|
bin | 1010111011000100110110… |
… | …1101000010010100000111 |
3 | 1120112010222210110020101111 |
4 | 2232301031231002110013 |
5 | 3033233021221224312 |
6 | 41313155503105451 |
7 | 2346460536262462 |
oct | 256611555022407 |
9 | 46463883406344 |
10 | 12010032211207 |
11 | 391047609a648 |
12 | 141b75b5a2287 |
13 | 691705c77634 |
14 | 2d74081282d9 |
15 | 15c61da428a7 |
hex | aec4db42507 |
12010032211207 has 2 divisors, whose sum is σ = 12010032211208. Its totient is φ = 12010032211206.
The previous prime is 12010032211183. The next prime is 12010032211231. The reversal of 12010032211207 is 70211223001021.
It is a balanced prime because it is at equal distance from previous prime (12010032211183) and next prime (12010032211231).
It is an emirp because it is prime and its reverse (70211223001021) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12010032211207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12010032211237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005016105603 + 6005016105604.
It is an arithmetic number, because the mean of its divisors is an integer number (6005016105604).
Almost surely, 212010032211207 is an apocalyptic number.
12010032211207 is a deficient number, since it is larger than the sum of its proper divisors (1).
12010032211207 is an equidigital number, since it uses as much as digits as its factorization.
12010032211207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 336, while the sum is 22.
Adding to 12010032211207 its reverse (70211223001021), we get a palindrome (82221255212228).
The spelling of 12010032211207 in words is "twelve trillion, ten billion, thirty-two million, two hundred eleven thousand, two hundred seven".
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