Base | Representation |
---|---|
bin | 10001011110100001111… |
… | …001101010001000101101 |
3 | 11020211000121012020120021 |
4 | 101132201321222020231 |
5 | 124134133100402112 |
6 | 2315423133522141 |
7 | 152525125412341 |
oct | 21364171521055 |
9 | 4224017166507 |
10 | 1201012122157 |
11 | 42338a03a491 |
12 | 174920643351 |
13 | 893411aa663 |
14 | 421b4b0d621 |
15 | 213939b3907 |
hex | 117a1e6a22d |
1201012122157 has 2 divisors, whose sum is σ = 1201012122158. Its totient is φ = 1201012122156.
The previous prime is 1201012122133. The next prime is 1201012122281. The reversal of 1201012122157 is 7512212101021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 694190578761 + 506821543396 = 833181^2 + 711914^2 .
It is a cyclic number.
It is not a de Polignac number, because 1201012122157 - 211 = 1201012120109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201012128157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600506061078 + 600506061079.
It is an arithmetic number, because the mean of its divisors is an integer number (600506061079).
Almost surely, 21201012122157 is an apocalyptic number.
It is an amenable number.
1201012122157 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201012122157 is an equidigital number, since it uses as much as digits as its factorization.
1201012122157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 560, while the sum is 25.
Adding to 1201012122157 its reverse (7512212101021), we get a palindrome (8713224223178).
The spelling of 1201012122157 in words is "one trillion, two hundred one billion, twelve million, one hundred twenty-two thousand, one hundred fifty-seven".
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