Base | Representation |
---|---|
bin | 10110010111101110… |
… | …00000101010000011 |
3 | 1011000000011211011112 |
4 | 23023313000222003 |
5 | 144044043130201 |
6 | 5303430433535 |
7 | 603423264263 |
oct | 131367005203 |
9 | 34000154145 |
10 | 12010130051 |
11 | 5103450517 |
12 | 23b22028ab |
13 | 11952a063a |
14 | 81d0d77a3 |
15 | 4a45c20bb |
hex | 2cbdc0a83 |
12010130051 has 2 divisors, whose sum is σ = 12010130052. Its totient is φ = 12010130050.
The previous prime is 12010130021. The next prime is 12010130053. The reversal of 12010130051 is 15003101021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12010130051 - 26 = 12010129987 is a prime.
Together with 12010130053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12010130053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005065025 + 6005065026.
It is an arithmetic number, because the mean of its divisors is an integer number (6005065026).
Almost surely, 212010130051 is an apocalyptic number.
12010130051 is a deficient number, since it is larger than the sum of its proper divisors (1).
12010130051 is an equidigital number, since it uses as much as digits as its factorization.
12010130051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30, while the sum is 14.
Adding to 12010130051 its reverse (15003101021), we get a palindrome (27013231072).
The spelling of 12010130051 in words is "twelve billion, ten million, one hundred thirty thousand, fifty-one".
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