120110000999957 has 2 divisors, whose sum is σ = 120110000999958. Its totient is φ = 120110000999956.

The previous prime is 120110000999941. The next prime is 120110001000001. The reversal of 120110000999957 is 759999000011021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96873349565476 + 23236651434481 = 9842426^2 + 4820441^2 .

It is a cyclic number.

It is not a de Polignac number, because 120110000999957 - 2⁴ = 120110000999941 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120110000999899 and 120110000999908.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120110000992957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60055000499978 + 60055000499979.

It is an arithmetic number, because the mean of its divisors is an integer number (60055000499979).

Almost surely, 2^{120110000999957} is an apocalyptic number.

It is an amenable number.

120110000999957 is a deficient number, since it is larger than the sum of its proper divisors (1).

120110000999957 is an equidigital number, since it uses as much as digits as its factorization.

120110000999957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 459270, while the sum is 53.

The spelling of 120110000999957 in words is "one hundred twenty trillion, one hundred ten billion, nine hundred ninety-nine thousand, nine hundred fifty-seven".